**Problem 301:**

A steel shaft 3 ft long that has a diameter of 4 in is subjected to a torque of 15 Kip.ft. Determine the maximum shearing stress and the angle of twist. Use G = 12 × 10

^{6}psi.

__Solution:__
Given,

Length, L= 3 ft = 3 x 12 in

Diameter, D = 4 in

Torque, T = 15 kip.ft = 15000 x 12 = 180000 psi.in

G = 12 × 10

^{6}psi.
Maximum Shearing stress, τ

_{max}= ?
Angle of twist, θ = ?

We know that, maximum shearing stress,

*So, the maximum shearing stress = 14.32 ksi*
We also know that, angle of twist,

**So, the angle of twist = 1.23**^{o}
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