**Problem 302:**

What is the minimum diameter of a solid steel shaft that will not twist
through more than 3° in a 6-m length when subjected to a torque of 12
kN·m? What maximum shearing stress is developed? Use G = 83 GPa.

__Solution:__
Given,

Length, L = 6 m

Torque, T = 12 KN.m

Angle of twist, θ = 3°

G = 83 GPa.

Minimum diameter, d =?

Maximum shearing stress, τ

_{max}=?
We know that , Angle of twist,

**So, Minimum diameter = 113.98 mm**

We also know that, maximum shearing stress,

*So, Maximum shearing stress = 41.27 MPa*
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