Problem 302: Torsion

Problem 302:
                    What is the minimum diameter of a solid steel shaft that will not twist through more than 3° in a 6-m length when subjected to a torque of 12 kN·m? What maximum shearing stress is developed? Use G = 83 GPa.


           Length, L = 6 m
           Torque, T = 12 KN.m
           Angle of twist, θ = 3°
           G = 83 GPa.
           Minimum diameter, d =?
           Maximum shearing stress, τmax =?

We know that , Angle of twist,

So, Minimum diameter = 113.98 mm
We also know that, maximum shearing stress,

So, Maximum shearing stress = 41.27 MPa

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