Problem 303:
A steel marine propeller shaft 14 in. in diameter and 18 ft long is used to transmit 5000 hp at 189 rpm. If G = 12 × 106 psi, determine the maximum shearing stress.
Solution:
Given,
Diameter, d = 14 in
Length, L = 18 ft = 18 x 12 in
Power, P = 5000 hp
Frequency, f = 189 rpm
G = 12 × 106 psi
Maximum shearing stress, τmax =?
1 hp = 33,000 ft·lb/min = 396,000 lb·in/min
We know that, torque:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEifiidtOL8FvZDsD7QFCqKB4R4nK5uWDudvmmSVi4ZOQf4Ai6KMvTR5e60J-_SRYaR2-0NmvcrIpTvNlAyCrrJX1Q-PXCKZWjuBq0gdg7ZSBGzVHVtaJSwAgoizMYGvLfxG98zduxJySd0/s1600/303-1.jpg)
We also know that, Maximum shearing stress:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiWUSxP6sQ9xmUttOyvzFyEaGebx5lrQm72VCFrdTOJztWV0hY3ZexGfOVobbnhQSUH7RQuWSz93ixxO7JUZtEeudpn2HT5XLvayQ07p9RfmEPOCXeATWnURIOKhLn6LnIwvLxarc1HVBM/s1600/303-2.jpg)
So, Maximum shearing stress = 3094.6 psi
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